0=16x^2+80x-2481

Solution for 0=16x^2+80x-2481 equation:

0=16x^2+80x-2481

We move all terms to the left:

0-(16x^2+80x-2481)=0

We add all the numbers together, and all the variables

-(16x^2+80x-2481)=0

We get rid of parentheses

-16x^2-80x+2481=0

a = -16; b = -80; c = +2481;
Δ = b2-4ac
Δ = -802-4·(-16)·2481
Δ = 165184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{165184}=\sqrt{64*2581}=\sqrt{64}*\sqrt{2581}=8\sqrt{2581}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-8\sqrt{2581}}{2*-16}=\frac{80-8\sqrt{2581}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+8\sqrt{2581}}{2*-16}=\frac{80+8\sqrt{2581}}{-32}
$